3x^-1-x=x(3x+1)+5

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Solution for 3x^-1-x=x(3x+1)+5 equation: 



3x^-1-x=x(3x+1)+5

We move all terms to the left:

3x^-1-x-(x(3x+1)+5)=0

We add all the numbers together, and all the variables

2x-(x(3x+1)+5)-1=0



We calculate terms in parentheses: -(x(3x+1)+5), so:

x(3x+1)+5

We multiply parentheses

3x^2+x+5

Back to the equation:

-(3x^2+x+5)



We get rid of parentheses

-3x^2+2x-x-5-1=0

We add all the numbers together, and all the variables

-3x^2+x-6=0

a = -3; b = 1; c = -6;
Δ = b2-4ac
Δ = 12-4·(-3)·(-6)
Δ = -71
Delta is less than zero, so there is no solution for the equation

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